What is the result of the calculation (88.9 g O / 1 atom) / (111 g H / 2 atoms)?

What is the result of the calculation (88.9 g O / 1 atom) / (111 g H / 2 atoms)?

• A. 8
• B. 16
• C. 32
• D. 64

Answer: (B)

To solve the calculation (88.9 g O / 1 atom) / (111 g H / 2 atoms), we start by simplifying both parts of the expression. First, we can interpret the expression as a ratio of the mass per atom of oxygen to the mass per atom of hydrogen. For oxygen, we have a mass of 88.9 g associated with 1 atom. This gives us a mass of 88.9 g for each oxygen atom. For hydrogen, we have a mass of 111 g for 2 atoms. Therefore, to find the mass for 1 atom of hydrogen, we divide 111 g by 2, resulting in 55.5 g per hydrogen atom. Next, we set up the calculation to find the ratio of the oxygen mass to the hydrogen mass per atom: 1. Mass of oxygen per atom: 88.9 g O 2. Mass of hydrogen per atom: 55.5 g H Now we perform the division: \[ \frac{88.9 \, \text{g O}}{55.5 \, \text{g H}} \] To compute this division, we divide 88.9 by 55.5, which

To solve the calculation (88.9 g O / 1 atom) / (111 g H / 2 atoms), we start by simplifying both parts of the expression.

First, we can interpret the expression as a ratio of the mass per atom of oxygen to the mass per atom of hydrogen.

For oxygen, we have a mass of 88.9 g associated with 1 atom. This gives us a mass of 88.9 g for each oxygen atom.

For hydrogen, we have a mass of 111 g for 2 atoms. Therefore, to find the mass for 1 atom of hydrogen, we divide 111 g by 2, resulting in 55.5 g per hydrogen atom.

Next, we set up the calculation to find the ratio of the oxygen mass to the hydrogen mass per atom:

1. Mass of oxygen per atom: 88.9 g O

2. Mass of hydrogen per atom: 55.5 g H

Now we perform the division:

[ \frac{88.9 , \text{g O}}{55.5 , \text{g H}} ]

To compute this division, we divide 88.9 by 55.5, which